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colSums (is.na( data)) # x1 x2 x3 # 2 1 0. colSums (is.na (data)) # x1 x2 x3 # 2 1 0. The RStudio console output shows the number of NA values for each of our variables. The variable x1 contains 2 NA values, the variable x2 contains 1 NA value, and the variable x3 contains no NA values.
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Source: R/count-tally.R (Optional) If omitted (and no variable named n exists in the data), will count the 175 1358
Hence, it is equivalent to rowSums(x == count, na.rm = TRUE) . However, this function is designed to work nicely within a pipe-workflow and allows select-helpers for selecting variables and the return value is always a data frame (with one variable).
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is there a simpler way to count the number of elements in a vector that are not NA than this: countN <- function (v) { return (Reduce (function (x, y) x + y, ifelse (is.na (v), 0, 1)))
If you are concerned that your row means are not correct because of NA's, just use the na.rm = TRUE argument in rowMeans. I want to count the number of NA values in a data frame column. Say my data frame is called df, and the name of the column I am considering is col. The way I have come up with is following: sapp There are a number of ways in R to count NAs (missing values).